關於Oracle數據庫的帳號,咱們在維護數據庫的時候,偶爾可能須要獲取一些特殊信息。例如,帳號的建立時間、帳號的狀態、帳號的鎖定時間.....。正常狀況下,咱們能夠經過DBA_USERS獲取大部分相關信息。可是有一些特殊信息,還必須經過不經常使用底層基表sys.user$來獲取。html
SQL> DESC DBA_USERS;
Name Null? Type
----------------------------------------- -------- ----------------------------
USERNAME NOT NULL VARCHAR2(30)
USER_ID NOT NULL NUMBER
PASSWORD VARCHAR2(30)
ACCOUNT_STATUS NOT NULL VARCHAR2(32)
LOCK_DATE DATE
EXPIRY_DATE DATE
DEFAULT_TABLESPACE NOT NULL VARCHAR2(30)
TEMPORARY_TABLESPACE NOT NULL VARCHAR2(30)
CREATED NOT NULL DATE
PROFILE NOT NULL VARCHAR2(30)
INITIAL_RSRC_CONSUMER_GROUP VARCHAR2(30)
EXTERNAL_NAME VARCHAR2(4000)
其實咱們常常使用的DBA_USERS是同義詞,對應SYS.DBA_USERS這個視圖。若是你想查看SYS.DBA_USERS的定義,能夠經過下面方式:sql
--ORACLE 10g
SQL>SELECT DBMS_METADATA.GET_DDL('VIEW', 'DBA_USERS', 'SYS') FROM DUAL;
CREATE OR REPLACE FORCE VIEW "SYS"."DBA_USERS" (
"USERNAME"
, "USER_ID"
, "PASSWORD"
, "ACCOUNT_STATUS"
, "LOCK_DATE"
, "EXPIRY_DATE"
, "DEFAULT_TABLESPACE"
, "TEMPORARY_TABLESPACE"
, "CREATED"
, "PROFILE"
, "INITIAL_RSRC_CONSUMER_GROUP"
, "EXTERNAL_NAME") AS
select u.name, u.user#, u.password,
m.status,
decode(u.astatus, 4, u.ltime,
5, u.ltime,
6, u.ltime,
8, u.ltime,
9, u.ltime,
10, u.ltime, to_date(NULL)),
decode(u.astatus,
1, u.exptime,
2, u.exptime,
5, u.exptime,
6, u.exptime,
9, u.exptime,
10, u.exptime,
decode(u.ptime, '', to_date(NULL),
decode(pr.limit#, 2147483647, to_date(NULL),
decode(pr.limit#, 0,
decode(dp.limit#, 2147483647, to_date(NULL), u.ptime +
dp.limit#/86400),
u.ptime + pr.limit#/86400)))),
dts.name, tts.name, u.ctime, p.name,
nvl(cgm.consumer_group, 'DEFAULT_CONSUMER_GROUP'),
u.ext_username
from sys.user$ u left outer join sys.resource_group_mapping$ cgm
on (cgm.attribute = 'ORACLE_USER' and cgm.status = 'ACTIVE' and
cgm.value = u.name),
sys.ts$ dts, sys.ts$ tts, sys.profname$ p,
sys.user_astatus_map m, sys.profile$ pr, sys.profile$ dp
where u.datats# = dts.ts#
and u.resource$ = p.profile#
and u.tempts# = tts.ts#
and u.astatus = m.status#
and u.type# = 1
and u.resource$ = pr.profile#
and dp.profile# = 0
and dp.type#=1
and dp.resource#=1
and pr.type# = 1
and pr.resource# = 1
經過上面的視圖定義,咱們能夠知道,大部分數據來自於底層基表sys.user$。關於表sys.user$的結構以下,咱們能夠從sql.bsq中能夠看到sys.user$的定義。數據庫
SQL> DESC sys.user$
Name Null? Type
----------------------------------------- -------- ----------------------------
USER# NOT NULL NUMBER
NAME NOT NULL VARCHAR2(30)
TYPE# NOT NULL NUMBER
PASSWORD VARCHAR2(30)
DATATS# NOT NULL NUMBER
TEMPTS# NOT NULL NUMBER
CTIME NOT NULL DATE
PTIME DATE
EXPTIME DATE
LTIME DATE
RESOURCE$ NOT NULL NUMBER
AUDIT$ VARCHAR2(38)
DEFROLE NOT NULL NUMBER
DEFGRP# NUMBER
DEFGRP_SEQ# NUMBER
ASTATUS NOT NULL NUMBER
LCOUNT NOT NULL NUMBER
DEFSCHCLASS VARCHAR2(30)
EXT_USERNAME VARCHAR2(4000)
SPARE1 NUMBER
SPARE2 NUMBER
SPARE3 NUMBER
SPARE4 VARCHAR2(1000)
SPARE5 VARCHAR2(1000)
SPARE6 DATE
其中,咱們能夠獲取一下關鍵字段信息,具體以下oracle
NAME 用戶(User)或角色(Role)的名字
TYPE# 0表示Role,1表示User
CTIME 用戶的建立時間
PTIME 密碼最後一次修改時間
EXPTIME 密碼過時的時間
LTIME 帳號最後一次鎖定的時間
LCOUNT 用戶登陸失敗次數。
下面咱們簡單測試驗證一下,app
SQL> CREATE USER TEST IDENTIFIED BY "Test#1232134$#3" DEFAULT TABLESPACE TBS_TEST_DATA TEMPORARY TABLESPACE TEMP;
User created.
SQL> GRANT CONNECT TO TEST;
SQL> @get_user_info.sql
Session altered.
Enter value for user_name: TEST
old 9: WHERE NAME=('&USER_NAME')
new 9: WHERE NAME=('TEST')
NAME TYPE# CTIME PTIME EXPTIME LTIME LCOUNT
------------------------------ ---------- ------------------- ------------------- ------------------- ------------------- ----------
TEST 1 2021-06-10 14:10:01 2021-06-10 14:10:01 0
SQL> ALTER USER TEST IDENTIFIED BY "kER124";
User altered.
SQL> @get_user_info.sql
Session altered.
Enter value for user_name: TEST
old 9: WHERE NAME=('&USER_NAME')
new 9: WHERE NAME=('TEST')
NAME TYPE# CTIME PTIME EXPTIME LTIME LCOUNT
------------------------------ ---------- ------------------- ------------------- ------------------- ------------------- ----------
TEST 1 2021-06-10 14:10:01 2021-06-10 14:10:50 0
SQL> ALTER USER TEST ACCOUNT LOCK;
User altered.
SQL> @get_user_info.sql
Session altered.
Enter value for user_name: TEST
old 9: WHERE NAME=('&USER_NAME')
new 9: WHERE NAME=('TEST')
NAME TYPE# CTIME PTIME EXPTIME LTIME LCOUNT
------------------------------ ---------- ------------------- ------------------- ------------------- ------------------- ----------
TEST 1 2021-06-10 14:10:01 2021-06-10 14:10:50 2021-06-10 14:11:27 0
SQL>
其中get_user_info.sql的腳本以下測試
$ more get_user_info.sql
ALTER SESSION SET NLS_DATE_FORMAT='YYYY-MM-DD HH24:MI:SS';
SELECT NAME
, TYPE#
, CTIME
, PTIME
, EXPTIME
, LTIME
, LCOUNT
FROM user$
WHERE NAME=('&USER_NAME');
另外,咱們來測試一下帳號登陸失敗次數,在實驗前先解鎖帳號,用錯誤的帳號密碼嘗試登陸數據庫,你會發現LCOUNT就變成1了。spa
SQL> @get_user_info.sql
Session altered.
Enter value for user_name: TEST
old 9: WHERE NAME=('&USER_NAME')
new 9: WHERE NAME=('TEST')
NAME TYPE# CTIME PTIME EXPTIME LTIME LCOUNT
------------------------------ ---------- ------------------- ------------------- ------------------- ------------------- ----------
TEST 1 2021-06-10 14:10:01 2021-06-10 14:10:50 2021-06-10 14:11:27 1
SQL>
那麼這個LCOUNT字段的值是一直累加到超過閾值鎖定呢?仍是中間會清零呢?什麼狀況下會清零呢? 若是你使用正確的密碼成功登陸數據庫後,你會發現LCOUNT的值就清零了。以下截圖所示:3d
$ sqlplus /nolog
SQL*Plus: Release 10.2.0.4.0 - Production on Thu Jun 10 14:30:41 2021
Copyright (c) 1982, 2007, Oracle. All Rights Reserved.
SQL> connect TEST
Enter password:
Connected.
也就是說,只要你在鎖定以前,一旦成功登陸以後,該計數會被清零。在有些版本中,因爲Bug,也會出現LCOUNT沒有正確反映登陸失敗次數的狀況,例如Lcount neither reset on correct login nor incremented after incorrect login thru JDBC (Doc ID 2675398.1)中記錄了這樣的Bug。另外,ORACLE 12C 後新增了一個功能,它會記錄用戶的最後一次登陸時間:SPARE6字段記錄用戶的最後一次登陸時間code
參考資料:orm
https://www.eygle.com/archives/2009/07/profile_failed_login_attempts.html
https://dbaora.com/sys-user-table-in-oracle-last-password-change-time-last-locked-last-expired-creation-time-failed-logon/
Lcount neither reset on correct login nor incremented after incorrect login thru JDBC (Doc ID 2675398.1)
https://bijoos.com/oraclenotes/2013/153/