最近在作遠程接口調用時,須要對數據進行加解密,所以返回的參數統一爲如下json格式java
{ "code":0, "msg":"成功", "sign":"abcdefghijkl", "timestamp":1491897441000, "data":{} }
首先,咱們假設傳輸過程當中的對象實體是json
user.javaide
public class User { private int id; private String name; ...省略get set... @Override public String toString() { return "User [id=" + id + ", name=" + name + "]"; } }
當返回的數據轉成對象時,可能存在三種狀況:測試
1. User 對象 2. List<User> list 對象 3. Page page
Page.javagoogle
public class Page<T> { private int page; private int size; private int total; private List<T> data; ...省略 get set... @Override public String toString() { return "User [page=" + page + ", size=" + size + ", total=" + total + ", data=" + data + "]"; } }
所以返回data的json可能爲如下三種:code
1.對象實體的json json -> User對象
{ "id":1, "name":"eric" }
2.對象實體列表的json json -> List<User> list接口
[ { "id":1, "name":"eric" }, { "id":2, "name":"john" } ]
3.分頁的實體json json -> Page<User> pageget
{ "page":1, "size":10, "total":2, "data":[ { "id":1, "name":"eric" }, { "id":2, "name":"john" } ] }
所以咱們須要寫一個公共類解決上述轉換問題it
GsonUtils.java
public class GsonUtils { private GsonUtils() { } public static <T>T fromJson(String json,Class<T> type){ Gson gson = new Gson(); return gson.fromJson(json,type); } public static <T> List<T> listFromJson(String json){ Gson gson = new Gson(); return gson.fromJson(json, new TypeToken<List<T>>(){}.getType()); } }
測試:
public class Main { public static void main(String[] args) { String json1 = "{\"id\":1,\"name\":\"eric\"}"; String json2 = "[{\"id\":1,\"name\":\"eric\"},{\"id\":2,\"name\":\"john\"}]"; String json3 = "{\"page\":1,\"size\":10,\"total\":2,\"data\":[{\"id\":1,\"name\":\"eric\"},{\"id\":2,\"name\":\"john\"}]}"; User user = GsonUtils.fromJson(json1, User.class); List<User> lists = GsonUtils.listFromJson(json2); Page<User> page = GsonUtils.fromJson(json3, Page.class); System.out.println("user:" + user); System.out.println("lists:" + lists); System.out.println("page:" + page); } }
運行後的結果:
user:User [id=1, name=eric] lists:[{id=1.0, name=eric}, {id=2.0, name=john}] page:User [page=1, size=10, total=2, list=[{id=1.0, name=eric}, {id=2.0, name=john}]]
此時已經成功將三種格式的json轉化爲Object,可是這裏有個問題以下:若是咱們用一下方法獲取user,就會報錯,由於處理Java反射TypeToken泛型運行時類型擦除
User user = lists.get(0);
Exception in thread "main" java.lang.ClassCastException: com.google.gson.internal.LinkedTreeMap cannot be cast to swun.test.entity.User at swun.test.Main.main(Main.java:27)
所以咱們將方法listFromJson修改成
public static <T> List<T> listFromJson(String json,Type type){ Gson gson = new Gson(); return gson.fromJson(json, type); }
在調用的時候,將具體的Type傳入
public class Main { public static void main(String[] args) { String json1 = "{\"id\":1,\"name\":\"eric\"}"; String json2 = "[{\"id\":1,\"name\":\"eric\"},{\"id\":2,\"name\":\"john\"}]"; String json3 = "{\"page\":1,\"size\":10,\"total\":2,\"data\":[{\"id\":1,\"name\":\"eric\"},{\"id\":2,\"name\":\"john\"}]}"; User user = GsonUtils.fromJson(json1, User.class); List<User> lists = GsonUtils.listFromJson(json2,new TypeToken<List<User>>(){}.getType()); Page<User> page = GsonUtils.fromJson(json3, Page.class); System.out.println("user:" + user); System.out.println("lists:" + lists); System.out.println("page:" + page); User user1 = lists.get(0); System.out.println("user1:" + user1); } }
運行結果以下:
user:User [id=1, name=eric] lists:[User [id=1, name=eric], User [id=2, name=john]] page:User [page=1, size=10, total=2, data=[{id=1.0, name=eric}, {id=2.0, name=john}]] user1:User [id=1, name=eric]