批量建立分表

有兩種方法：

１，在mysql中建立存儲過程，而後執行

存儲過程以下:

USE tobresume;

DROP PROCEDURE IF EXISTS Proc;

DELIMITER $$

CREATE PROCEDURE Proc()

BEGIN

DECLARE db_name VARCHAR(20);
DECLARE table_name VARCHAR(20);
DECLARE table_pro CHAR(18);
DECLARE sql_text VARCHAR(3000);
DECLARE i INT;
DECLARE j VARCHAR(2);

SET db_name='tobresume';
SET table_name='';
SET table_pro ='_talent_dir_resume';
SET sql_text='';
SET i=0;
SET j='';

WHILE i<=128 DO
IF i<10 THEN
SET j=CONCAT('0',i);
ELSE
SET j=LPAD(LCASE(HEX(i)),2,'0');
END IF;

SET table_name=CONCAT(j,table_pro);

SET sql_text=CONCAT('CREATE TABLE IF NOT EXISTS ', db_name,'.',table_name, '(
id int(11) NOT NULL AUTO_INCREMENT,
uid int(11) unsigned NOT NULL DEFAULT 0 COMMENT \'用戶帳號ID\',
top_id int(11) unsigned NOT NULL DEFAULT 0 COMMENT \'集團帳號ID\',
dir_id int(11) unsigned NOT NULL DEFAULT 0 COMMENT \'自定義文件夾ID\',
parent_id int(11) unsigned NOT NULL DEFAULT 0 COMMENT \'父帳號ID\',
resume_id bigint(20) unsigned NOT NULL DEFAULT 0 COMMENT \'簡歷ID\',
is_deleted tinyint(1) unsigned NOT NULL DEFAULT 0 COMMENT \'是否被刪除：1.是 0.否\',
created int(11) NOT NULL DEFAULT 0 COMMENT \'建立時間\',
updated int(11) NOT NULL DEFAULT 0 COMMENT \'更新時間\',
PRIMARY KEY (id),
UNIQUE KEY unique_uid_dirid_cvid (uid,dir_id,resume_id)
) ENGINE=InnoDB AUTO_INCREMENT=0 DEFAULT CHARSET=utf8 COMMENT=\'人才庫簡歷文件夾對應關係表\'');

SELECT sql_text;
SET @sql_text=sql_text;
PREPARE stmt FROM @sql_text;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;
SET i=i+1;
END WHILE;

END$$

DELIMITER ;

call Proc();

結果以下:

| sql_text                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                              |
+--------------------------------------------------------------------------------------------------
| CREATE TABLE IF NOT EXISTS tobresume.80_talent_dir_resume(
id int(11) NOT NULL AUTO_INCREMENT,
uid int(11) unsigned NOT NULL DEFAULT 0 COMMENT '用戶帳號ID',

top_id int(11) unsigned NOT NULL DEFAULT 0 COMMENT '集團帳號ID',

dir_id int(11) unsigned NOT NULL DEFAULT 0 COMMENT '自定義文件夾ID',

parent_id int(11) unsigned NOT NULL DEFAULT 0 COMMENT '父帳號ID',

resume_id bigint(20) unsigned NOT NULL DEFAULT 0 COMMENT '簡歷ID',

is_deleted tinyint(1) unsigned NOT NULL DEFAULT 0 COMMENT '是否被刪除：1.是 0.否',

created int(11) NOT NULL DEFAULT 0 COMMENT '建立時間',

updated int(11) NOT NULL DEFAULT 0 COMMENT '更新時間',

PRIMARY KEY (id),
UNIQUE KEY unique_uid_dirid_cvid (uid,dir_id,resume_id)
) ENGINE=InnoDB AUTO_INCREMENT=0 DEFAULT CHARSET=utf8 COMMENT='人才庫簡歷文件夾對應關係表'                                                 |
+---------------------------------------------------------------------------------------------------
1 row in set (38.44 sec)

Query OK, 0 rows affected (38.90 sec)

生成129張分表共耗時38.44秒.

第二種方法是shell腳本

#!/bin/bash

MYSQLPATH=`echo 'mysql -h192.168.1.201 -udevuser -pdevuser;'`;
DB_NAME='tobresume';
TABLES_NAME='talent_dir_resume';

for i in `seq 128`;
do
        j=`echo 'obase=16;' $i | bc | tr '[A-z]' '[a-z]'`;
        x=`echo $j | awk '{print length($0)}'`;
        if [ $x -lt 2 ];then
                j="0"$j
        fi
        ALTER_SQL_1="USE $DB_NAME;set names utf8;CREATE TABLE IF NOT EXISTS ${j}_$TABLES_NAME (
                id int(11) NOT NULL AUTO_INCREMENT,
                uid int(11) unsigned NOT NULL DEFAULT '0' COMMENT '用戶帳號ID',
                top_id int(11) unsigned NOT NULL DEFAULT '0' COMMENT '集團帳號ID',
                dir_id int(11) unsigned NOT NULL DEFAULT '0' COMMENT '自定義文件夾ID',
                parent_id int(11) unsigned NOT NULL DEFAULT '0' COMMENT '父帳號ID',
                resume_id bigint(20) unsigned NOT NULL DEFAULT '0' COMMENT '簡歷ID',
                is_deleted tinyint(1) unsigned NOT NULL DEFAULT '0' COMMENT '是否被刪除：1.是 0.否',
                created int(11) NOT NULL DEFAULT '0' COMMENT '建立時間',
                updated int(11) NOT NULL DEFAULT '0' COMMENT '更新時間',
                PRIMARY KEY (id),
                UNIQUE KEY unique_uid_dirid_cvid (uid, dir_id, resume_id)
                ) ENGINE=InnoDB AUTO_INCREMENT=0 DEFAULT CHARSET=utf8 COMMENT='人才庫簡歷文件夾對應關係表'"
        echo "正在建立${j}_$TABLES_NAME表"
        $MYSQLPATH -e "$ALTER_SQL_1"
done

這種方法的缺點就是每次建立都要去連數據庫，頗有可能被拒絕訪問。以下

正在建立80_talent_dir_resume表
mysql: [Warning] Using a password on the command line interface can be insecure.
ERROR 1045 (28000): Access denied for user 'devuser'@'192.168.1.140' (using password: YES)

 

參考:

http://zhaoshijie.iteye.com/blog/2280570

https://blog.csdn.net/a__yes/article/details/52795793