- json字符串----->json對象
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使用JSON.parse()函數swift
var jsonStr = '{"name":"zhangsan","age":23,"email":"chentging@aliyun.com"}'; var json = JSON.parse(jsonStr); console.log(json);//輸出:Object {name: "zhangsan", age: 23, email: "chentging@aliyun.com"}
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使用eval()函數後端
var jsonStr = '{"name":"zhangsan","age":23,"email":"chentging@aliyun.com"}'; var json = eval ("(" + jsonStr + ")"); console.log(json);//輸出:Object {name: "zhangsan", age: 23, email: "chentging@aliyun.com"}
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使用jQuery插件jQuery.parseJSON()ruby
var jsonStr = '{"name":"zhangsan","age":23,"email":"chentging@aliyun.com"}'; var json = jQuery.parseJSON(jsonStr); console.log(json);//輸出:Object {name: "zhangsan", age: 23, email: "chentging@aliyun.com"}
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- json對象------>json字符串
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使用JSON.stringify()函數
var json = {name: "zhangsan", age: 23, email: "chentging@aliyun.com"}; var jsonStr = JSON.stringify(json); console.log(jsonStr);//輸出:"{"name":"zhangsan","age":23,"email":"chentging@aliyun.com"}"
- 把數據在先後端之間傳遞,須要把json對象轉換爲json字符串