【轉自】http://blog.csdn.net/marising/article/details/4567531函數
網上江湖郎中和蒙古大夫不少,所以,此類帖子也不少。關於排序,我還真沒研究過,看了江湖郎中和蒙古大夫的帖子,搞了半天不行,因此,本身研究了一 下,以下:三種方式均可以,如重寫<,()和寫比較函數compare_index。可是要注意對象和對象指針的排序區別。spa
容器中是對象時,用<排序。.net
容器中是對象指針時,用()和比較函數排序均可以。指針
list用成員方法sortcode
vector用sort函數對象
部分排序blog
#include<algorithm>排序
std::partial_sort(.begin(), mid, .end());it
class TestIndex{ public: int index; TestIndex(){ } TestIndex(int _index):index(_index){ } bool operator()(const TestIndex* t1,const TestIndex* t2){ printf("Operator():%d,%d/n",t1->index,t2->index); return t1->index < t2->index; } bool operator < (const TestIndex& ti) const { printf("Operator<:%d/n",ti.index); return index < ti.index; } }; bool compare_index(const TestIndex* t1,const TestIndex* t2){ printf("CompareIndex:%d,%d/n",t1->index,t2->index); return t1->index < t2->index; } int main(int argc, char** argv) { list<TestIndex*> tiList1; list<TestIndex> tiList2; vector<TestIndex*> tiVec1; vector<TestIndex> tiVec2; TestIndex* t1 = new TestIndex(2); TestIndex* t2 = new TestIndex(1); TestIndex* t3 = new TestIndex(3); tiList1.push_back(t1); tiList1.push_back(t2); tiList1.push_back(t3); tiList2.push_back(*t1); tiList2.push_back(*t2); tiList2.push_back(*t3); tiVec1.push_back(t1); tiVec1.push_back(t2); tiVec1.push_back(t3); tiVec2.push_back(*t1); tiVec2.push_back(*t2); tiVec2.push_back(*t3); printf("tiList1.sort()/n"); tiList1.sort();//沒法正確排序 printf("tiList2.sort()/n"); tiList2.sort();//用<比較 printf("tiList1.sort(TestIndex())/n"); tiList1.sort(TestIndex());//用()比較 printf("sort(tiVec1.begin(),tiVec1.end())/n"); sort(tiVec1.begin(),tiVec1.end());//沒法正確排序 printf("sort(tiVec2.begin(),tiVec2.end())/n"); sort(tiVec2.begin(),tiVec2.end());//用<比較 printf("sort(tiVec1.begin(),tiVec1.end(),TestIndex())/n"); sort(tiVec1.begin(),tiVec1.end(),TestIndex());//用()比較 printf("sort(tiVec1.begin(),tiVec1.end(),compare_index)/n"); sort(tiVec1.begin(),tiVec1.end(),compare_index);//用compare_index比較 return 0; }