關於π的近似值

#include #includeusing namespace std; int main() {double an=1,sn=0.0,a=1.0; int b=1; while(abs(an)>=1e-8) {sn+=an; a+=2; b=-b; an=b/a;} cout << 「π的值是」<<4*sn<<endl; return 0;}ios ［求π的近似值，π/4=1-1/3+1/5…

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