1、節點node
//節點的數據結構 private static class Node<E> { E item; //元素 Node<E> next; //後繼 Node<E> prev; //前驅 Node(Node<E> prev, E element, Node<E> next) { this.item = element; this.next = next; this.prev = prev; } }
2、構造函數數據結構
//無參構造函數 public LinkedList() { } //構造一個包含指定集合的元素的列表 public LinkedList(Collection<? extends E> c) { this(); addAll(c); }
插入一個元素後,first和last都指向這個元素函數
/** * index :Collection第一個元素插入的位置 */ public boolean addAll(int index, Collection<? extends E> c) { //檢測下標的合法性 checkPositionIndex(index); Object[] a = c.toArray(); int numNew = a.length; if (numNew == 0) return false; Node<E> pred, succ; //集合中沒有一個元素,講前驅節點指向last,後繼爲null if (index == size) { succ = null; pred = last; } else { //獲取index位置的節點,後繼節點爲當前的節點,前驅節點爲當前節點的前驅節點。 succ = node(index); pred = succ.prev; } for (Object o : a) { @SuppressWarnings("unchecked") E e = (E) o; //創建新的節點 Node<E> newNode = new Node<>(pred, e, null); if (pred == null) first = newNode; else pred.next = newNode; pred = newNode; } if (succ == null) { last = pred; } else { pred.next = succ; succ.prev = pred; } size += numNew; modCount++; return true; }
獲取指定位置的節點this
/** * 若是index在集合的前半部分則從前邊遍歷, * 若是在集合的後半部分則從後邊遍歷。提升效率。 */ Node<E> node(int index) { if (index < (size >> 1)) { Node<E> x = first; for (int i = 0; i < index; i++) x = x.next; return x; } else { Node<E> x = last; for (int i = size - 1; i > index; i--) x = x.prev; return x; } }
將元素添加到首尾元素spa
//將元素添加爲首元素 private void linkFirst(E e) { final Node<E> f = first; final Node<E> newNode = new Node<>(null, e, f); first = newNode; if (f == null) last = newNode; else f.prev = newNode; size++; modCount++; } //將元素做爲尾元素 void linkLast(E e) { final Node<E> l = last; final Node<E> newNode = new Node<>(l, e, null); last = newNode; if (l == null) first = newNode; else l.next = newNode; size++; modCount++; }