[Swift]LeetCode547. 朋友圈 | Friend Circles

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There are N students in a class. Some of them are friends, while some are not. Their friendship is transitive in nature. For example, if A is a directfriend of B, and B is a direct friend of C, then A is an indirect friend of C. And we defined a friend circle is a group of students who are direct or indirect friends.

Given a N*N matrix M representing the friend relationship between students in the class. If M[i][j] = 1, then the ith and jth students are directfriends with each other, otherwise not. And you have to output the total number of friend circles among all the students.

Example 1:

Input: 
[[1,1,0],
 [1,1,0],
 [0,0,1]]
Output: 2
Explanation:The 0th and 1st students are direct friends, so they are in a friend circle. 
The 2nd student himself is in a friend circle. So return 2. 

Example 2:

Input: 
[[1,1,0],
 [1,1,1],
 [0,1,1]]
Output: 1
Explanation:The 0th and 1st students are direct friends, the 1st and 2nd students are direct friends, 
so the 0th and 2nd students are indirect friends. All of them are in the same friend circle, so return 1.

Note:

1. N is in range [1,200].
2. M[i][i] = 1 for all students.
3. If M[i][j] = 1, then M[j][i] = 1.

---

班上有 N 名學生。其中有些人是朋友，有些則不是。他們的友誼具備是傳遞性。若是已知 A 是 B 的朋友，B 是 C 的朋友，那麼咱們能夠認爲 A 也是 C 的朋友。所謂的朋友圈，是指全部朋友的集合。

給定一個 N * N 的矩陣 M，表示班級中學生之間的朋友關係。若是M[i][j] = 1，表示已知第 i 個和 j 個學生互爲朋友關係，不然爲不知道。你必須輸出全部學生中的已知的朋友圈總數。

示例 1:

輸入: 
[[1,1,0],
 [1,1,0],
 [0,0,1]]
輸出: 2 
說明：已知學生0和學生1互爲朋友，他們在一個朋友圈。
第2個學生本身在一個朋友圈。因此返回2。

示例 2:

輸入: 
[[1,1,0],
 [1,1,1],
 [0,1,1]]
輸出: 1
說明：已知學生0和學生1互爲朋友，學生1和學生2互爲朋友，因此學生0和學生2也是朋友，因此他們三個在一個朋友圈，返回1。

注意：

1. N 在[1,200]的範圍內。
2. 對於全部學生，有M[i][i] = 1。
3. 若是有M[i][j] = 1，則有M[j][i] = 1。

---

180ms

 1 class Solution {
 2     func findCircleNum(_ M: [[Int]]) -> Int {
 3         var count = 0
 4         var visited: [Int] = [Int](repeating: 0, count: M.count)
 5         for i in 0...(M.count - 1) {
 6             if visited[i] == 0 {
 7                 self.dfs(M, &visited, i)
 8                 count += 1
 9             }
10         }
11         
12         return count
13     }
14     
15     func dfs(_ M : [[Int]], _ visited: inout [Int], _ i: Int){
16         
17         for j in 0...(M.count  - 1) {
18             if M[i][j] == 1 && visited[j] == 0 {
19                 visited[j] = 1
20                 dfs(M, &visited, j)
21             }
22         }
23     }    
24 }

---

Runtime: 184 ms

Memory Usage: 19 MB

 1 class Solution {
 2     //經典思路:聯合查找Union Find
 3     func findCircleNum(_ M: [[Int]]) -> Int {
 4         var n:Int = M.count
 5         var res:Int = n
 6         var root:[Int] = [Int](repeating:0,count:n)
 7         for i in 0..<n
 8         {
 9             root[i] = i
10         }
11         for i in 0..<n
12         {
13             for j in (i + 1)..<n
14             {
15                 if M[i][j] == 1
16                 {
17                     var p1:Int = getRoot(&root, i)
18                     var p2:Int = getRoot(&root, j)
19                     if p1 != p2
20                     {
21                         res -= 1
22                         root[p2] = p1                        
23                     }
24                 }
25                 
26             }
27         }
28         return res
29     }
30     
31     func getRoot(_ root:inout [Int],_ i:Int) -> Int
32     {
33         var i = i
34         while(i != root[i])
35         {
36             root[i] = root[root[i]]
37             i = root[i]
38         }
39         return i
40     }
41 }

---

184ms

 1 class Solution {
 2     func findCircleNum(_ M: [[Int]]) -> Int {
 3         var ans = 0
 4         
 5         let size = M.count
 6         var visited = [Bool].init(repeating: false, count: size)
 7         var current = 0
 8         func DFS(_ cur: Int) {
 9             guard !visited[cur] else {
10                 return
11             }
12             visited[cur] = true
13             for i in 0 ..< size {
14                 if !visited[i] && M[cur][i] == 1 {
15                     DFS(i)
16                 }
17             }
18         }
19         for i in 0 ..< size where !visited[i] {
20             ans += 1
21             DFS(i)
22         }
23         return ans
24     }
25 }

---

188ms

 1 class Solution {
 2     func findCircleNum(_ matrix: [[Int]]) -> Int {
 3         guard !matrix.isEmpty else {
 4             return 0
 5         }
 6         
 7         let n = matrix.count
 8         
 9         var visitedStudents = [Bool](repeating: false, count: n)
10         var numOfCircles = 0
11         
12         for student in 0..<n {
13             if visitedStudents[student] {
14                 continue
15             }
16             
17             numOfCircles += 1
18             visitFriends(student: student, matrix: matrix, visitedStudents: &visitedStudents)
19         }
20         
21         return numOfCircles
22     }
23     
24     func visitFriends(student: Int, matrix: [[Int]], visitedStudents: inout [Bool]) {
25         visitedStudents[student] = true
26         
27         for friend in 0..<matrix.count {
28             guard matrix[student][friend] == 1 else {
29                 continue
30             }
31             guard !visitedStudents[friend] else {
32                 continue
33             }
34             
35             visitFriends(student: friend, matrix: matrix, visitedStudents: &visitedStudents)
36         }
37     }
38 }

---

192ms

 1 class Solution {
 2     func findCircleNum(_ M: [[Int]]) -> Int {
 3         var visited = Set<Int>()
 4         var num = 0
 5         for i in 0..<M.count {
 6             if !visited.contains(i) {
 7                 self.recurse(i, M, &visited)
 8                 num += 1
 9             }
10         }
11         return num
12     }
13     
14     func recurse(_ node: Int, _ graph: [[Int]], _ visited: inout Set<Int>) {
15         visited.insert(node)
16         for i in 0..<graph.count {
17             if !visited.contains(i) && graph[node][i] > 0 {
18                 recurse(i, graph, &visited)
19             }
20         }
21     }
22 }

---

196ms

 1 class Solution {
 2     func findCircleNum(_ M: [[Int]]) -> Int {
 3         guard M.count > 0 && M[0].count > 0 else {
 4             return 0
 5         }
 6         
 7         var unionFind = UnionFind<Int>()
 8         
 9         for row in 0..<M.count {
10             for column in 0..<M[row].count {
11                 if M[row][column] == 1 {
12                     unionFind.addSet(row)
13                     unionFind.addSet(column)
14                     unionFind.union(row, column)
15                 }
16             }
17         }
18         
19         return unionFind.numerOfSets
20     }
21 }
22 
23 
24 public struct UnionFind<T: Hashable> {
25     private var index: [T: Int] = [:]
26     private var parent: [Int] = []
27     private var size: [Int] = []
28     public var numerOfSets: Int = 0 
29     
30     public mutating func addSet(_ element: T) {
31         if index[element] == nil {
32             index[element] = parent.count
33             parent.append(parent.count)
34             size.append(1)
35             numerOfSets += 1
36         }
37     }
38     
39     public mutating func find(_ element: T) ->Int? {
40         guard let index = index[element] else {
41             return nil 
42         }
43         return setByIndex(index)
44     }
45     
46     private mutating func setByIndex(_ index: Int) -> Int {
47         if parent[index] == index {
48             return index 
49         } else {
50             parent[index] = setByIndex(parent[index])
51             return parent[index]
52         }
53     }
54     
55     public mutating func union(_ element1: T, _ element2: T) {
56         guard let set1 = find(element1), let set2 = find(element2) else {
57             return 
58         }
59         
60         if set1 != set2 {
61             numerOfSets -= 1 
62             if size[set1] > size[set2] {
63                 parent[set2] = set1 
64                 size[set1] += size[set2]
65             } else {
66                 parent[set1] = set2 
67                 size[set2] += size[set1]
68             }
69         }
70     }
71 }

---

200ms

 1 class Solution {
 2     class UnionFind {
 3         private var parent: [Int]
 4         private (set) var count = 0
 5         
 6         init(size: Int, count: Int) {
 7             self.parent = Array(0..<size)
 8             self.count = count
 9         }
10 
11         func union(_ x: Int, _ y: Int) {
12             let px = find(x)
13             let py = find(y)
14             if px != py {
15                 parent[px] = py
16                 count -= 1
17             }
18         }
19 
20         func find(_ x: Int) -> Int {
21             if parent[x] == x {
22                 return x
23             }
24             parent[x] = find(parent[x])
25             return parent[x]
26         }
27     }
28 
29     func findCircleNum(_ M: [[Int]]) -> Int {
30         if M.isEmpty || M[0].isEmpty {
31             return 0
32         }
33 
34         let n = M.count
35         let unionFind = UnionFind(size: n, count: n)
36 
37         for y in 0..<n {
38             for x in 0..<n {
39                 if x != y, M[y][x] == 1 {
40                     unionFind.union(x, y)
41                 }
42             }
43         }
44         return unionFind.count
45     }
46 }

---

212ms

 1 class UnionFind {
 2     private var connectivities: [Int]
 3     private var sizes: [Int]
 4     init(size: Int) {
 5         self.connectivities = [Int](repeating: 0, count: size)
 6         self.sizes = [Int](repeating: 1, count: size)
 7         for i in 0..<size {
 8             connectivities[i] = i
 9         }
10     }
11     func connect(n1: Int, n2: Int) {
12         guard let root1 = root(of: n1),
13             let root2 = root(of: n2),
14             root1 != root2 else { return }
15         let sz1 = sizes[root1]
16         let sz2 = sizes[root2]
17         if sz1 > sz2 {
18             connectivities[root2] = root1
19             sizes[root1] += sizes[root2]
20         } else {
21             connectivities[root1] = root2
22             sizes[root2] += sizes[root1]
23         }
24     }
25     func isConnected(n1: Int, n2: Int) -> Bool {
26         return root(of: n1) == root(of: n2)
27     }
28     func root(of n: Int) -> Int? {
29         guard n < connectivities.count else { return nil }
30         let parent = connectivities[n]
31         if parent == n {
32             return n
33         }
34         guard let rt = root(of: parent) else { return nil }
35         connectivities[n] = rt
36         return rt
37     }
38     func snapshot() {
39         print("c: \(connectivities)")
40         print("s: \(sizes)")
41     }
42 }
43 
44 class Solution {
45     func findCircleNum(_ M: [[Int]]) -> Int {
46         let size = M.count
47         let uf = UnionFind(size: size)
48         for (y, row) in M.enumerated() {
49             for (x, _) in row.enumerated() {
50                 if x <= y {
51                     continue
52                 }
53                 if M[y][x] == 1 {
54                     uf.connect(n1: y, n2: x)
55                 }
56             }
57         }
58         var groupSet = Set<Int>()
59         for i in 0..<M.count {
60             guard let root = uf.root(of: i) else { continue }
61             groupSet.insert(root)
62         }
63         return groupSet.count
64     }
65 }

---

216ms

 1 class Solution {
 2     func findCircleNum(_ M: [[Int]]) -> Int {
 3         var visited: Set<Int> = Set<Int>()
 4         var res = 0
 5         var q: [Int] = []
 6         for i in 0..<M.count {
 7             if !visited.contains(i) {
 8                 res += 1
 9                 q.append(i)
10                 while !q.isEmpty {
11                     let friend = q.removeFirst()
12                     if !visited.contains(friend) {
13                         visited.insert(friend)
14                         for j in 0..<M[friend].count {
15                             if M[friend][j] == 1 {
16                                 q.append(j)
17                             }
18                         }
19                     }
20                 }
21             }
22         }
23         return res
24     }
25 }

---

228ms

 1 class Solution {
 2     func findCircleNum(_ M: [[Int]]) -> Int {
 3         
 4         var sum = 0
 5         var circle = M
 6         let mCount = M.count
 7         for i in 0 ..< mCount {
 8             let isCircle = p_circle(&circle, down: i, right: i, s: mCount)
 9             if isCircle {  sum += 1 }
10         }
11         return sum
12     }
13     
14     func p_circle(_ circle: inout [[Int]], down: Int, right: Int, s: Int) -> Bool {
15         guard
16             down < s,
17             right <= down,
18             circle[down][right] == 1
19             else { return false }
20         circle[down][right] = 0
21         circle[right][down] = 0
22 
23         var r = 0
24         if down == 0 { r = 1 }
25         while (r < s) {
26             if circle[down][r] == 1 {
27                 _ = p_circle(&circle, down: r, right: r, s: s)
28             }
29             r += 1
30             if down == r { r += 1 }
31         }
32         return true
33     }
34 }

---

328ms

 1 class FriendCircle {
 2     var friends: Set<Int> = []
 3 }
 4 
 5 extension FriendCircle: Hashable {
 6     var hashValue: Int {
 7         return ObjectIdentifier(self).hashValue
 8     }
 9     
10     static func ==(lhs: FriendCircle, rhs: FriendCircle) -> Bool {
11         return lhs === rhs
12     }
13 }
14 
15 
16 class Solution {
17     func findCircleNum(_ matrix: [[Int]]) -> Int {
18         guard !matrix.isEmpty else {
19             return 0
20         }
21         
22         let n = matrix.count
23         var numOfCircles = 0
24         var personToCircle = [FriendCircle?](repeating: nil, count: n)
25         
26         for column in 0..<n {
27             
28             var friends: Set<Int> = []
29             var circles: Set<FriendCircle> = []
30             
31             for row in 0..<n {
32                 if matrix[row][column] == 1 {
33                     friends.insert(row)
34                     
35                     if let existingCircle = personToCircle[row] {
36                         circles.insert(existingCircle)
37                     }
38                 }
39             }
40             
41             let circle: FriendCircle
42             if circles.count > 1 {
43                 for circle in circles {
44                     friends.formUnion(circle.friends)
45                 }
46                 circle = FriendCircle()
47                 numOfCircles -= circles.count-1
48             } else if let existingCircle = circles.first {
49                 circle = existingCircle
50             } else {
51                 circle = FriendCircle()
52                 numOfCircles += 1
53             }
54             
55             
56             for friend in friends {
57                 circle.friends.insert(friend)
58                 personToCircle[friend] = circle
59             }
60         }       
61         return numOfCircles
62     }
63 }

---

352ms

 1 class Solution {
 2     
 3     private var circles: [Int] = []
 4     private var count = 0
 5     
 6     func connect(_ index: Int, _ index2: Int) {
 7         let af = find(index)
 8         let bf = find(index2)
 9         guard af != bf else {
10             return
11         }
12         
13         for index in 0..<circles.count {
14             if circles[index] == af {
15                 circles[index] = bf
16             }
17         }
18         
19         count -= 1
20     }
21     
22     func find(_ index: Int) -> Int {
23         if index >= 0 && index < circles.count {
24             return circles[index]
25         } else {
26             return -1
27         }
28     }
29     
30     func findCircleNum(_ M: [[Int]]) -> Int {
31         guard !M.isEmpty && !M[0].isEmpty else {
32             return 0    
33         }
34         
35         count = M.count
36         for index in 0..<M.count {
37             circles.append(index)
38         }
39         
40         for row in 0..<M.count {
41             for column in 0..<M[row].count {
42                 if row != column && M[row][column] == 1 { 
43                     connect(row, column)
44                 }
45             }
46         }
47         
48         return count
49     }
50 }

---

384ms

 1 class Solution {
 2     var pre:[Int]
 3     init() {
 4         self.pre = [Int]()
 5     }
 6     func findCircleNum(_ M: [[Int]]) -> Int {
 7        
 8         if (M.count > 0) {
 9             self.pre = [Int](repeating: 0, count: M.count)
10             for (i, v) in pre.enumerated() {
11                 pre[i] = i
12             }
13             for i in 0...M.count - 1 {
14                  if (M[i].count == M.count) {
15                     for j in 0...M[i].count - 1 {
16                          // print("a loop 1")
17                         if (M[i][j] == 1) {
18                             join(i, j)
19                         }
20                     }
21                  } else {
22                      return 0 //異常數據
23                  }
24             }
25             var count = 0
26             for (i, v) in pre.enumerated() {
27                 if (i == v) {
28                     count+=1
29                 }
30             }
31             // print("\(count)")
32             return count
33         }
34         return 0
35     }
36     
37     func join( _ i:Int, _ j:Int) {
38         var preI = find(i)
39         var preJ = find(j)
40         if (preI != preJ) {
41             self.pre[preI] = preJ
42         }
43         // print("\(self.pre)")
44     }
45     func find(_ i:Int)->Int {
46         var i = i
47         while (self.pre[i] != i) {
48             i = self.pre[i]
49         }
50         return i
51     }
52 }

---

400ms

 1 class Solution {
 2     func findCircleNum(_ M: [[Int]]) -> Int {
 3         var ret = 0
 4         var visited:Array<Bool> = Array(repeating: false, count: M.count)
 5         func getFriend(_ y:Int) {
 6             for x in 0..<M.count {
 7                 if !visited[x] && M[y][x] == 1{
 8                     visited[y] = true
 9                     getFriend(x)
10                 }
11             }
12         }
13         guard M.count > 0 else {
14             return ret
15         }
16         for y in 0..<M.count {
17             if(!visited[y]) {
18                 ret += 1
19                 getFriend(y)
20             }
21         }
22         return ret
23     }
24 }