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Educational Codeforces Round 83 (Rated for Div. 2) B. Bogosort
時間 2020-07-26
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B. Bogosort 題目連接-B. Bogosort 題目大意 輸入一個數組a[],作任意屢次交換操做,使得對於任意j < i,恆有j−a[j]≠i−a[i]ios 解題思路c++ 由於j−a[j]≠i−a[i] ,移項得j - i≠a[j]-a[i],易得遞減序列就是知足這個條件的 遞減隊列對任意j < i,都有j-i<0,a[j]-a[i]≥0,因此知足條件 sort+逆序輸出便可 附上代
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相關文章
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Educational Codeforces Round 83 (Rated for Div. 2) A - C
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Educational Codeforces Round 83 (Rated for Div. 2)
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