015-W命令

 輸入w 命令

[root@Carlton scripts]# w
 18:38:17 up 2 days,  2:32,  4 users,  load average: 0.00, 0.00, 0.00
USER     TTY      FROM              LOGIN@   IDLE   JCPU   PCPU WHAT
carlton  tty1     :0               Sun16    2days  7.21s  0.01s pam: gdm-password
carlton  pts/0    :0.0             Sun16    2days  0.01s  0.21s gnome-terminal
root     pts/1    119.145.10.77    18:28    0.00s  0.00s  0.00s w
root     tty7     :1               Sun16    2days  6.38s  6.38s /usr/bin/Xorg :1 -br -verbose -audit 4 -auth /var/run/gdm/auth-for-gdm-OyUK2i/database -nolisten tcp

Users:表明有幾個用戶登陸

注意的地方有: load average 0.00,0.00,0.00  

load average後面3個數字分別表明的意思是：

1分鐘內的系統負載

5分鐘內的平均負載

15分鐘內的平均負載

這個數值的大小參照於你服務器的CPU個數 

數值除以服務器的個數，大於1，則服務器繁忙，小於1則服務器正常

那麼如何查看服務器的個數呢？  見下圖

[root@Carlton scripts]# cat /proc/cpuinfo 
processor       : 0
vendor_id       : GenuineIntel
cpu family      : 6
model           : 79
model name      : Intel(R) Xeon(R) CPU E5-2682 v4 @ 2.50GHz
stepping        : 1
microcode       : 1
cpu MHz         : 2494.222
cache size      : 40960 KB
physical id     : 0
siblings        : 1
core id         : 0
cpu cores       : 1
apicid          : 0
initial apicid  : 0
fpu             : yes
fpu_exception   : yes
cpuid level     : 13
wp              : yes
flags           : fpu vme de pse tsc msr pae mce cx8 apic sep mtrr pge mca cmov pat pse36 clflush mmx fxsr sse sse2 ss syscall nx pdpe1gb rdtscp lm constant_tsc up rep_good unfair_spinlock pni pclmulqdq ssse3 fma cx16 pcid sse4_1 sse4_2 x2apic movbe popcnt tsc_deadline_timer aes xsave avx f16c rdrand hypervisor lahf_lm abm 3dnowprefetch xsaveopt fsgsbase bmi1 hle avx2 smep bmi2 erms invpcid rtm rdseed adx
bogomips        : 4988.44
clflush size    : 64
cache_alignment : 64
address sizes   : 46 bits physical, 48 bits virtual
power management:

[root@Carlton scripts]# grep -c 'processor' /proc/cpuinfo 
1