C++ Redis mset 二進制數據接口封裝方案git
C++中使用hiredis客戶端接口訪問redis;
須要使用mset一次設置多個二進制數據github
如下給出三種封裝實現方案;redis
在redis-cli中,mset的語法是這樣的:數組
/opt/colin$./redis-cli mset a 11 b 22 c 333 OK
按照這樣的語法拼接後,直接使用hiredis字符串接口redisCommand傳遞:安全
void msetNotBinary(redisContext *c, const vector<string> &vtKey, const vector<string> & vtVal ) { if(vtKey.size() != vtVal.size()) { throw runtime_error( "Redis error" ); } string strCmd = "MSET"; for(int i = 0; i < vtKey.size(); i++) { strCmd += " "+vtKey[i]+" "+vtVal[i]; } cout << "strCmd:" << strCmd << endl; void * r = redisCommand(c, strCmd.c_str() ); if ( !r ) throw runtime_error( "Redis error" ); freeReplyObject( r ); } void do_test( redisContext *c ) { vector<string> vtKey; vector<string> vtVal; vtKey.push_back("A"); vtVal.push_back("AAAA"); vtKey.push_back("B"); vtVal.push_back("BBBB"); vtKey.push_back("C"); vtVal.push_back("CCCC"); //add a binary data vtKey.push_back("D"); vtVal.push_back(""); char a[] = "ABCDE"; a[2] = 0; vtVal[3].assign(a,5); try { msetNotBinary(c, vtKey, vtVal ); //mset1( c, vtKey, vtVal ); //mset2( c, vtKey, vtVal ); } catch ( runtime_error & ) { cout << "Error" << endl; } } int main(int argc, char *argv[]) { redisContext *c; c = redisConnect("127.0.0.1",6379); if (c->err) { cout << "Connection error: " << c->errstr << endl; return -1; } do_test(c); redisFree(c); return 0; }
這種方式能夠處理mset多個字符串數據,但對於數據內容爲二進制數據的無能爲力;app
對於多個參數傳遞,hiredis提供瞭如下接口,這個接口中最後一個參數是全部的傳入數據的內容長度,
就是說這個接口是二進制安全的:code
void *redisCommandArgv(redisContext *c, int argc, const char **argv, const size_t *argvlen);
主要工做就是構造一個動態的二維數組char ** argv,其中涉及到char **到const char **的轉換,有必定的風險,
關於這一點前一篇文章已經談到;blog
void mset1( redisContext *c, const vector<string> &vtKey, const vector<string> & vtVal ) { if(vtKey.size() != vtVal.size()) { throw runtime_error( "Redis error" ); } char ** argv = new char*[vtKey.size() + vtVal.size() + 1 ]; size_t * argvlen = new size_t[vtKey.size() + vtVal.size() + 1 ]; int j = 0; argv[j] = new char[5]; memcpy(argv[j],"MSET",4); argvlen[j] = 4; ++j; for(int i = 0 ; i < vtKey.size();i++) { argvlen[j] = vtKey[i].length(); argv[j] = new char[argvlen[j]]; memset((void*)argv[j],0,argvlen[j] ); memcpy((void*)argv[j],vtKey[i].data(),vtKey[i].length()); j++; argvlen[j] = vtVal[i].length(); argv[j] = new char[argvlen[j]]; memset((void*)argv[j],0,argvlen[j]); memcpy((void*)argv[j],vtVal[i].data(),vtVal[i].length()); j++; } //if not use const_cast<const char**> ,compile error //for why assign from char** to const char** error, see my blog ... void *r = redisCommandArgv(c, vtKey.size() + vtVal.size() + 1, const_cast<const char**>(argv), argvlen ); if ( !r ) throw runtime_error( "Redis error" ); freeReplyObject( r ); for(int i = 0;i < vtKey.size();i++) { delete [] argv[i]; argv[i] = NULL; } delete []argv; delete []argvlen; argv = NULL; }
仍是使用redisCommandArgv接口,使用vector來構造這個const char **,這個方法是從參考資料1中學到的:接口
void mset2( redisContext *c, const vector<string> &vtKey, const vector<string> & vtVal) { if(vtKey.size() != vtVal.size()) { throw runtime_error( "Redis error" ); } vector<const char *> argv( vtKey.size() + vtVal.size() + 1 ); vector<size_t> argvlen( vtKey.size() + vtVal.size() + 1 ); int j = 0; static char msetcmd[] = "MSET"; argv[j] = msetcmd; argvlen[j] = sizeof(msetcmd)-1; ++j; for(int i = 0;i< vtKey.size();++i) { argvlen[j] = vtKey[i].length(); argv[j] = new char[argvlen[j]]; memset((void*)argv[j],0,argvlen[j] ); memcpy((void*)argv[j],vtKey[i].data(),vtKey[i].length()); j++; argvlen[j] = vtVal[i].length(); argv[j] = new char[argvlen[j]]; memset((void*)argv[j],0,argvlen[j]); memcpy((void*)argv[j],vtVal[i].data(),vtVal[i].length()); j++; } void *r = redisCommandArgv(c, argv.size(), &(argv[0]), &(argvlen[0]) );
for(int i = 0; i < argv.size();i++)
{
delete argv[i];
argv[i] = NULL;
}
if ( !r ) throw runtime_error( "Redis error" ); freeReplyObject( r ); }
這樣,就實現二進制數據的傳遞;字符串
程序執行後,能夠用redis-cli來驗證:
對於非二進制安全的實現,二進制內容是截斷的: /opt/app/colin$./redis-cli get D "AB" 而二進制安全的實現接口,二進制數據的0經過轉義方式顯示: /opt/app/colin$./redis-cli get D "AB\x00DE"
完整可執行的代碼詳見github:https://github.com/me115/cppset/tree/master/2DimArray
https://gist.github.com/dspezia/1455082
Posted by: 大CC | 8JAN,2015
博客:blog.me115.com [訂閱]
微博:新浪微博