在switch中的case語句中聲明變量編譯出錯的解決方案

在switch中的case語句中聲明變量編譯的問題

先來看段代碼,別管什麼意思:

case 10: int i = 0, j = 0; for (i = 0; i < 11; i++) recive_phone[i] = msgbuf.text[i]; recive_phone[i] = '\0'; printf("%s文件%s函數%d行:接收端號碼:%s\n", __FILE__ , __FUNCTION__, __LINE__, recive_phone); for (j = 0; msgbuf.text[i] != '\0' && j < 12; i++,j++) center_phone[j] = msgbuf.text[i]; center_phone[j] = '\0'; printf("%s文件%s函數%d行:發送端號碼:%s\n", __FILE__ , __FUNCTION__, __LINE__, center_phone); break;

我在case:break中聲明瞭變量,結果gcc編譯時就提示:

error: a label can only be part of a statement and a declaration is not a statement

有下面三種方法處理:

一、將變量定義放到case：break外面；

二、將case：break中間的語句用{}包含；

case 10: { int i = 0, j = 0; for (i = 0; i < 11; i++) recive_phone[i] = msgbuf.text[i]; recive_phone[i] = '\0'; printf("%s文件%s函數%d行:接收端號碼:%s\n", __FILE__ , __FUNCTION__, __LINE__, recive_phone); for (j = 0; msgbuf.text[i] != '\0' && j < 12; i++,j++) center_phone[j] = msgbuf.text[i]; center_phone[j] = '\0'; printf("%s文件%s函數%d行:發送端號碼:%s\n", __FILE__ , __FUNCTION__, __LINE__, center_phone); } break;

注意case後{}括號

三、在「case：」後面加「；」處理。

case 10: ; int i = 0, j = 0; for (i = 0; i < 11; i++) recive_phone[i] = msgbuf.text[i]; recive_phone[i] = '\0'; printf("%s文件%s函數%d行:接收端號碼:%s\n", __FILE__ , __FUNCTION__, __LINE__, recive_phone); for (j = 0; msgbuf.text[i] != '\0' && j < 12; i++,j++) center_phone[j] = msgbuf.text[i]; center_phone[j] = '\0'; printf("%s文件%s函數%d行:發送端號碼:%s\n", __FILE__ , __FUNCTION__, __LINE__, center_phone); break;