根據經緯度算距離 | SQL

--計算地球上兩個座標點（經度，緯度）之間距離sql函數
CREATE FUNCTION [dbo].[fnGetDistance](@LatBegin REAL, @LngBegin REAL, @LatEnd REAL, @LngEnd REAL) RETURNS FLOAT
  AS
BEGIN
  --距離(公里)
  DECLARE @Distance REAL
  DECLARE @EARTH_RADIUS REAL
  SET @EARTH_RADIUS = 6378.137 
  DECLARE @RadLatBegin REAL,@RadLatEnd REAL,@RadLatDiff REAL,@RadLngDiff REAL
  SET @RadLatBegin = @LatBegin *PI()/180.0 
  SET @RadLatEnd = @LatEnd *PI()/180.0 
  SET @RadLatDiff = @RadLatBegin - @RadLatEnd 
  SET @RadLngDiff = @LngBegin *PI()/180.0 - @LngEnd *PI()/180.0  
  SET @Distance = 2 *ASIN(SQRT(POWER(SIN(@RadLatDiff/2), 2)+COS(@RadLatBegin)*COS(@RadLatEnd)*POWER(SIN(@RadLngDiff/2), 2)))
  SET @Distance = @Distance * @EARTH_RADIUS 
  --SET @Distance = Round(@Distance * 10000) / 10000 
  RETURN @Distance
END
/*
財富廣場
經度：114.02644397853898
緯度：22.536917850961675
光大銀行
經度:114.02633400796937
緯度:22.537137898472157
*/
SELECT id,name,dbo.fnGetDistance(114.02633400796937,22.537137898472157,gislng,gislat) as 距離  FROM yx_nurse
SELECT dbo.fnGetDistance(114.02633400796937,22.537137898472157,gislng,gislat) as 距離,yx_nurse.*  FROM yx_nurse WHERE dbo.fnGetDistance(114.02633400796937,22.537137898472157,gislng,gislat) < 0.100