[Bash]LeetCode194. 轉置文件 | Transpose File

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Given a text file file.txt, transpose its content.

You may assume that each row has the same number of columns and each field is separated by the ' ' character.

Example:

If file.txt has the following content:

name age
alice 21
ryan 30

Output the following:

name alice ryan
age 21 30

---

給定一個文件 file.txt，轉置它的內容。

你能夠假設每行列數相同，而且每一個字段由 ' ' 分隔.

示例:

假設 file.txt 文件內容以下：

name age
alice 21
ryan 30

應當輸出：

name alice ryan
age 21 30

---

12ms

 1 # Read from the file file.txt and print its transposed content to stdout.
 2 
 3 awk '
 4 BEGIN { hasBegan = 0 }
 5 {
 6         if (hasBegan == 0) {
 7                 for (ii = 1; ii <= NF; ii += 1) {
 8                         arr[ii] = $ii;
 9                 }
10                 hasBegan = 1;
11         } else {
12                 for (ii = 1; ii <= NF; ii += 1) {
13                         arr[ii] = arr[ii]" "$ii;
14                 }
15         }
16 }
17 END {
18         for (ii = 1; ii <= length(arr); ii += 1) {
19                 print arr[ii];
20         }
21 }
22 ' file.txt

---

136ms

 1 #!/bin/bash
 2 # Read from the file file.txt and print its transposed content to stdout
 3 
 4 lines=()
 5 
 6 while read line
 7 do
 8   i=0
 9   for word in $line
10   do
11     if (( ${#lines[i]} > 0 )); then lines[i]+=" "; fi
12     lines[i]+="$word"
13     ((i++))
14   done
15 done < "file.txt"
16 
17 last=$((${#lines[@]}-1))
18 
19 for k in $(seq 0 $last)
20 do
21   echo "${lines[$k]}"
22 done

---

168ms

1 # Read from the file file.txt and print its transposed content to stdout.
2 while read -a line; do
3     for ((i = 0; i < "${#line[@]}"; ++i)); do
4         a[$i]="${a[$i]} ${line[$i]}"
5     done
6 done < file.txt
7 for ((i = 0; i < ${#a[@]}; ++i)); do
8     echo ${a[i]}
9 done