問題:spa
The Employee
table holds all employees including their managers. Every employee has an Id, and there is also a column for the manager Id.code
+----+-------+--------+-----------+ | Id | Name | Salary | ManagerId | +----+-------+--------+-----------+ | 1 | Joe | 70000 | 3 | | 2 | Henry | 80000 | 4 | | 3 | Sam | 60000 | NULL | | 4 | Max | 90000 | NULL | +----+-------+--------+-----------+
Given the Employee
table, write a SQL query that finds out employees who earn more than their managers. For the above table, Joe is the only employee who earns more than his manager.對象
+----------+ | Employee | +----------+ | Joe | +----------+
解決:it
① 生成兩個實例對象進行內交經過ManagerId和Id,而後限制條件是一個Salary大於另外一個便可。2139 mstable
SELECT e1.Name Employee
FROM Employee e1 JOIN Employee e2 ON e1.ManagerId = e2.Id
WHERE e1.Salary > e2.Salary;tab
② 能夠不用Join,直接把條件都寫到where裏也行。1487 msdi
SELECT e1.Name Employee FROM Employee e1,Employee e2
WHERE e1.ManagerId = e2.Id AND e1.Salary > e2.Salary;query