[Swift]LeetCode695. 島嶼的最大面積 | Max Area of Island

★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★
➤微信公衆號:山青詠芝(shanqingyongzhi)
➤博客園地址:山青詠芝(https://www.cnblogs.com/strengthen/
➤GitHub地址:https://github.com/strengthen/LeetCode
➤原文地址: http://www.javashuo.com/article/p-bcddaskf-me.html 
➤若是連接不是山青詠芝的博客園地址,則多是爬取做者的文章。
➤原文已修改更新!強烈建議點擊原文地址閱讀!支持做者!支持原創!
★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★html

Given a non-empty 2D array grid of 0's and 1's, an island is a group of 1's (representing land) connected 4-directionally (horizontal or vertical.) You may assume all four edges of the grid are surrounded by water.git

Find the maximum area of an island in the given 2D array. (If there is no island, the maximum area is 0.)github

Example 1:數組

[[0,0,1,0,0,0,0,1,0,0,0,0,0],
 [0,0,0,0,0,0,0,1,1,1,0,0,0],
 [0,1,1,0,1,0,0,0,0,0,0,0,0],
 [0,1,0,0,1,1,0,0,1,0,1,0,0],
 [0,1,0,0,1,1,0,0,1,1,1,0,0],
 [0,0,0,0,0,0,0,0,0,0,1,0,0],
 [0,0,0,0,0,0,0,1,1,1,0,0,0],
 [0,0,0,0,0,0,0,1,1,0,0,0,0]]

Given the above grid, return 6. Note the answer is not 11, because the island must be connected 4-directionally.微信

Example 2:app

[[0,0,0,0,0,0,0,0]]

Given the above grid, return 0.spa

Note: The length of each dimension in the given grid does not exceed 50.code


給定一個包含了一些 0 和 1的非空二維數組 grid , 一個 島嶼 是由四個方向 (水平或垂直) 的 1 (表明土地) 構成的組合。你能夠假設二維矩陣的四個邊緣都被水包圍着。orm

找到給定的二維數組中最大的島嶼面積。(若是沒有島嶼,則返回面積爲0。)htm

示例 1:

[[0,0,1,0,0,0,0,1,0,0,0,0,0],
 [0,0,0,0,0,0,0,1,1,1,0,0,0],
 [0,1,1,0,1,0,0,0,0,0,0,0,0],
 [0,1,0,0,1,1,0,0,1,0,1,0,0],
 [0,1,0,0,1,1,0,0,1,1,1,0,0],
 [0,0,0,0,0,0,0,0,0,0,1,0,0],
 [0,0,0,0,0,0,0,1,1,1,0,0,0],
 [0,0,0,0,0,0,0,1,1,0,0,0,0]]

對於上面這個給定矩陣應返回 6。注意答案不該該是11,由於島嶼只能包含水平或垂直的四個方向的‘1’。

示例 2:

[[0,0,0,0,0,0,0,0]]

對於上面這個給定的矩陣, 返回 0

注意: 給定的矩陣grid 的長度和寬度都不超過 50。


Runtime: 76 ms
Memory Usage: 20 MB
 1 class Solution {
 2     func maxAreaOfIsland(_ grid: [[Int]]) -> Int {
 3         var tempGrid = grid
 4         var area = 0
 5         let m = tempGrid.count
 6         var n = 0
 7         var islandMax = 0
 8         for i in 0..<m {
 9             n = tempGrid[i].count
10             for j in 0..<n {
11                 area = 0
12                 area = dfs(i, j, m, n, &tempGrid, &area)
13                 islandMax = max(islandMax, area)
14             }
15         }
16         return islandMax    
17     }
18     
19     func dfs(_ i: Int,_ j: Int,_ m: Int,_ n:Int,_ grid: inout [[Int]],_ tempArea: inout Int) -> Int {
20         if i<0 || i>=m || j<0 || j>=n || grid[i][j] == 0 {
21             return tempArea
22         }
23         grid[i][j] = 0
24         tempArea += 1
25         tempArea = dfs(i+1, j, m, n, &grid, &tempArea)
26         tempArea = dfs(i-1, j, m, n, &grid, &tempArea)
27         tempArea = dfs(i, j+1, m, n, &grid, &tempArea)
28         tempArea = dfs(i, j-1, m, n, &grid, &tempArea)
29         return tempArea
30     }
31 }

80ms

 1 class Solution {
 2     func maxAreaOfIsland(_ grid: [[Int]]) -> Int {
 3         var dp:[[Int]] = grid
 4         var mX: Int = 0
 5         
 6         for i in 0 ..< dp.count {
 7             for j in 0 ..< dp[0].count {
 8                 // print("i:\(i) j:\(j)")
 9                 if dp[i][j] == 1 {
10                     mX = max(mX, area(&dp,i,j))
11                 }
12             }
13         }
14         
15         return mX
16     }
17     
18     func area(_ dp: inout [[Int]], _ i:Int, _ j:Int) -> Int {
19         if i < dp.count && i >= 0 && j < dp[0].count && j >= 0 && dp[i][j] == 1 {
20             dp[i][j] = 0
21             return 1 + area(&dp, i-1, j) + area(&dp, i+1, j) + area(&dp, i, j-1) + area(&dp, i, j+1)
22         }
23         return 0
24     }
25 }

92ms

 1 class Solution {
 2     var height = 0
 3     var width = 0
 4     
 5     var grid: [[Int]]!
 6     var visited: [[Bool]]!
 7     
 8     func maxAreaOfIsland(_ grid: [[Int]]) -> Int {
 9         height = grid.count
10         width = grid[0].count
11         
12         self.grid = grid
13         
14         var maxSize = 0
15         visited = Array(repeating:Array(repeating: false, count: width), count: height)
16         
17         for y in 0..<grid.count {
18             for x in 0..<grid[0].count {
19                 if grid[y][x] == 1 && visited[y][x] == false {
20                     let size = visitIsland(x: x, y: y)
21                     if size > maxSize {
22                         maxSize = size
23                     }
24                 }
25             }
26         }
27         return maxSize
28     }
29     
30     
31     func visitIsland(x: Int, y: Int) -> Int {
32      //   print("visit island x: \(x) y: \(y)")
33         if x < 0 || y < 0 || x >= width || y >= height {
34             return 0
35         }
36         if grid[y][x] == 0 || visited[y][x] == true {
37             return 0
38         }
39         visited[y][x] = true
40         var size = 1
41         size = size + visitIsland(x: x-1, y: y)
42         size = size + visitIsland(x: x+1, y: y)
43         size = size + visitIsland(x: x, y: y-1)
44         size = size + visitIsland(x: x, y: y+1)
45         return size
46     }
47 }

108ms

 1 class Solution {
 2     var maxCount = 0
 3     let transform = [[0,1],[0,-1],[1,0],[-1,0]]
 4     func maxAreaOfIsland(_ grid: [[Int]]) -> Int {
 5         var grid = grid
 6         for i in 0..<grid.count {
 7             for j in 0..<grid[0].count {
 8                 if grid[i][j] == 1 {
 9                     let count = dfs(&grid, i, j)
10                     if maxCount < count {
11                         maxCount = count 
12                     }
13                 }
14             }
15         }
16         return maxCount
17     }
18     
19     func dfs(_ grid: inout [[Int]], _ x: Int, _ y: Int) -> Int {
20         if x >= 0 && x < grid.count && y >= 0 && y < grid[0].count && grid[x][y] == 1 {
21             grid[x][y] = 0
22             var count = 1
23             for i in 0..<4 {
24                 let xx = x + transform[i][0]
25                 let yy = y + transform[i][1]
26                 count = count + dfs(&grid, xx, yy)
27             }   
28             return count
29         } else {
30             return 0
31         }
32     }
33 }

108ms

 1 class Solution {
 2     func maxAreaOfIsland(_ grid: [[Int]]) -> Int {
 3   var maxArea = 0
 4   var grid = grid
 5   for i in 0..<grid.count {
 6     for j in 0..<grid[i].count {
 7       if grid[i][j] == 1 {
 8         maxArea = max(maxArea, area(&grid, i, j))
 9       }
10     }
11   }
12   return maxArea
13 }
14 
15 func area(_ grid:inout[[Int]], _ i: Int, _ j: Int) -> Int {
16   var size = 0
17   if(i>=0 && i<grid.count && j>=0 && j<grid[0].count && grid[i][j]==1) {
18     grid[i][j] = 0
19     size = 1 + 
20     area(&grid, i+1, j) + 
21     area(&grid, i-1, j) + 
22     area(&grid, i, j-1) + 
23     area(&grid, i, j+1)
24   }
25   return size
26 }
27 }

112ms

 1 class Solution {
 2     func maxAreaOfIsland(_ grid: [[Int]]) -> Int {
 3         if grid.isEmpty || grid[0].isEmpty { return 0 }
 4         var res = 0
 5         var grid = grid
 6         let m = grid.count, n = grid[0].count
 7         for i in 0..<m {
 8             for j in 0..<n {
 9                 if grid[i][j] == 0 { continue }
10                 var count = 0
11                 var worklist = [(i, j)]
12                 while !worklist.isEmpty {
13                     let (x, y) = worklist.popLast()!
14                     if grid[x][y] == 0 { continue }
15                     grid[x][y] = 0
16                     count += 1
17                     if x > 0  { worklist.append((x - 1, y)) }
18                     if y > 0 { worklist.append((x, y - 1)) }
19                     if x < m - 1 { worklist.append((x + 1, y)) }
20                     if y < n - 1 { worklist.append((x, y + 1)) }
21                 }
22                 res = max(res, count)
23             }
24         }
25         return res
26     }
27 }

132 ms

 1 class Solution {
 2     var dirs:[[Int]] = [[0,-1],[-1,0],[0,1],[1,0]]
 3     func maxAreaOfIsland(_ grid: [[Int]]) -> Int {
 4         var grid = grid
 5         var m:Int = grid.count
 6         var n:Int = grid[0].count
 7         var res:Int = 0
 8         for i in 0..<m
 9         {
10             for j in 0..<n
11             {
12                 if grid[i][j] != 1
13                 {
14                     continue
15                 }
16                 var cnt:Int = 0
17                 var q:[(Int,Int)] = [(i,j)]
18                 grid[i][j] *= -1
19                 while (!q.isEmpty)
20                 {
21                     var t:(Int,Int) = q.first!
22                     q.removeFirst()
23                     cnt += 1
24                     res = max(res, cnt)                    
25                     for dir in dirs
26                     {
27                         var x:Int = t.0 + dir[0]
28                         var y:Int = t.1 + dir[1]
29                         if x < 0 || x >= m || y < 0 || y >= n || grid[x][y] <= 0
30                         {
31                             continue
32                         }
33                         grid[x][y] *= -1
34                         q.append((x, y))
35                     }
36                 }
37             }
38         }
39         return res
40     }
41 }
相關文章
相關標籤/搜索