Given an array of integers where 1 ≤ a[i] ≤ n (n = size of array), some elements appear twice and others appear once.app
Find all the elements of [1, n] inclusive that do not appear in this array.this
Could you do it without extra space and in O(n) runtime? You may assume the returned list does not count as extra space.spa
Example:code
Input: [4,3,2,7,8,2,3,1] Output: [5,6]
class Solution { public List<Integer> findDisappearedNumbers(int[] nums) { List<Integer> res = new ArrayList<>(); if (nums == null || nums.length == 0) return res; for (int i = 0; i < nums.length; i++) { int index = nums[i] > 0 ? nums[i]-1 : -nums[i]-1; if (nums[index] < 0) continue; nums[index] *= -1; } for (int i = 0; i < nums.length; i++) { if (nums[i] > 0) res.add(i+1); } return res; } }