MySQL 查詢in操做,查詢結果按in集合順序顯示 複製代碼 代碼以下:string
select * from test where id in(3,1,5) order by find_in_set(id,'3,1,5'); select * from test where id in(3,1,5) order by substring_index('3,1,2',id,1);test