Freemarker問答:

需求:在工做中解決的一些問題感受不夠「優美」。因此把這些問題貼出來,但願有更好操做的大牛不吝賜教。前端

第一問:Freemarker模擬「三元表達式」功能json

答: ${(orderpaydetail.loginViewList[0] = "390")?string('醫療保險','養老保險')}數組

第二問:Freemarker 獲得前端字符串中英文分割的數字並遍歷,格式以下:字符串

                        A100B200C350D490E530F690G770H890string

答:  <!-- 替換返回中的英文爲「,」,方便後期將字符串轉爲集合 -->
            <#assign Source=(orderpaydetail.attributeItems['hth'])>
            <#assign FirstGrade=Source?replace('A', '', 'i')?replace('B', ',', 'i')?replace('C', ',', 'i')?replace('D', ',', 'i')?replace('E', ',', 'i')?replace('F', ',', 'i')>
            <#assign SecondGrade=FirstGrade?replace('G', ',', 'i')?replace('H', ',', 'i')?replace('I', ',', 'i')?replace('J', ',', 'i')?replace('K', ',', 'i')?replace('L', ',', 'i')>
            <#assign ThirdGrade=SecondGrade?replace('M', ',', 'i')?replace('N', ',', 'i')?replace('O', ',', 'i')?replace('P', ',', 'i')?replace('Q', ',', 'i')?replace('R', ',', 'i')>
            <#assign FourthGrade=ThirdGrade?replace('S', ',', 'i')?replace('T', ',', 'i')?replace('U', ',', 'i')?replace('V', ',', 'i')?replace('W', ',', 'i')?replace('X', ',', 'i')>
            <#assign FifthGrade=FourthGrade?replace('Y', ',', 'i')?replace('Z', ',', 'i')>it

<select  id="payGrade">
                            <option value="0">請選擇</option>
                                  <#list FifthGrade?split(",") as grade>
                                      <option   value="${grade}" >
                                       ${grade}元</option>
                                  </#list>io

 </select>List

第三問:Freemarker遍歷json數組select

答: <#list [{"ysls":"2017122101","sfny":"201712"},{"ysls":"2017122234","sfny":"201734"}] as json> ${(json['ysls'])!''}  ${(json['sfny'])!''}</#list>遍歷

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